古今大战80分破解 (2千字)
古今大战80分破解：下载地址：http://www.wj2000.50megs.com
破解工具：softice
输入：
序列号：123456
注册码：78787878
用bpx hmemcpy作断点，中断后清除断点，再按12次F12，就到下面：
:004557BD E8B690FCFF call 0041E878
:004557C2 8B45F8 mov eax, dword ptr [ebp-08] //来到这里
:004557C5 E8B218FBFF call 0040707C
:004557CA 8BD8 mov ebx, eax
:004557CC 33C0 xor eax, eax
:004557CE 5A pop edx
:004557CF 59 pop ecx
:004557D0 59 pop ecx
:004557D1 648910 mov dword ptr fs:[eax], edx
:004557D4 EB14 jmp 004557EA
:004557D6 E961DBFAFF jmp 0040333C
:004557DB E800DEFAFF call 004035E0
:004557E0 E9AB000000 jmp 00455890
:004557E5 E8F6DDFAFF call 004035E0
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004557D4(U)
|
:004557EA 81FB48890100 cmp ebx, 00018948
:004557F0 7C14 jl 00455806
:004557F2 81FB52890100 cmp ebx, 00018952
:004557F8 7F0C jg 00455806
:004557FA 8D55FC lea edx, dword ptr [ebp-04]
:004557FD 8BC3 mov eax, ebx
:004557FF E890FBFFFF call 00455394
:00455804 EB0A jmp 00455810
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:004557F0(C), :004557F8(C)
|
:00455806 8D55FC lea edx, dword ptr [ebp-04]
:00455809 8BC3 mov eax, ebx
:0045580B E804FCFFFF call 00455414
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00455804(U)
|
:00455810 8D55F8 lea edx, dword ptr [ebp-08]
:00455813 8B86F0010000 mov eax, dword ptr [esi+000001F0]
:00455819 E85A90FCFF call 0041E878
:0045581E 8B45F8 mov eax, dword ptr [ebp-08]
:00455821 8B55FC mov edx, dword ptr [ebp-04]
:00455824 E87BE6FAFF call 00403EA4 //关键的call追入
:00455829 7554 jne 0045587F
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00455824(U)
|
00403EA4 push ebx
00403EA5 push esi
00403EA6 push edi
00403EA7 mov esi,eax
00403EA9 mov edi,edx
00403EAB cmp eax,edx //下d eax 可以看到假注册码：78787878 下d edx 可以看到真的注册码:QGBOFWCUOEERC
00403EAD jz 00403F42
（文：zhaocuo）
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