破文一篇，和和 (2千字)

敏思法律文书编辑（普及版）
破解方法
工具：w32dasm,hiew640
先用w32dasm反汇编
* Reference To: MSVCRT._mbscmp, Ord:0159h
                                  |
:00401AC2 FF1520064100            Call dword ptr [00410620]
:00401AC8 83C408                  add esp, 00000008
:00401ACB 85C0                    test eax, eax
:00401ACD 53                      push ebx
:00401ACE 7530                    jne 00401B00============>改此处为74就ok了
* Reference To: MFC42.Ordinal:0339, Ord:0339h
                                  |
:00401AD0 E859C00000              Call 0040DB2E
:00401AD5 83C404                  add esp, 00000004
:00401AD8 8D4C240C                lea ecx, dword ptr [esp+0C]
:00401ADC C7442418FFFFFFFF        mov [esp+18], FFFFFFFF
* Reference To: MFC42.Ordinal:0320, Ord:0320h
                                  |
:00401AE4 E8DBC00000              Call 0040DBC4
:00401AE9 5F                      pop edi
:00401AEA 5E                      pop esi
:00401AEB B801000000              mov eax, 00000001
:00401AF0 5B                      pop ebx
:00401AF1 8B4C2404                mov ecx, dword ptr [esp+04]
:00401AF5 64890D00000000          mov dword ptr fs:[00000000], ecx
:00401AFC 83C410                  add esp, 00000010
:00401AFF C3                      ret

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00401ACE(C)
|
* Reference To: MFC42.Ordinal:0339, Ord:0339h
                                  |
:00401B00 E829C00000              Call 0040DB2E
:00401B05 83C404                  add esp, 00000004
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00401ABA(C)
|
:00401B08 6A00                    push 00000000
:00401B0A 6A00                    push 00000000
* Possible StringData Ref from Data Obj ->"注册码错误! 正确注册后，才可以使用"
                                  |
:00401B0C 680C614100              push 0041610C
* Reference To: MFC42.Ordinal:04B0, Ord:04B0h
太简单，没什么写的，就是要注意在w32dasm中的地址与hiew中地址转化的方法，看雪教程中有详细介绍，我就不多说了
我还全靠bnbnf大哥，提醒呢，和和

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